highly significantp < 0.01
(7) Y = −2328.88741 + 6.06A + 115.61B + 11.84C + 13.65D + 0.014AB + 0.0044AC + 0.011AD + 0.031BD − 0.22CD − 0.41A 2 − 1.56B 2 − 0.21C 2 − 0.47D 2 Analysis of variance (ANOVA) confirmed that the model was highly significant ( p < 0.01) with a non-significant lack of fit ( p > 0.05).